What is (\partial)/(\partial x)(2xy-4x) ?

The answer to (\partial)/(\partial x)(2xy-4x) is 2y-4

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(\partial)/(\partial x)(2xy-4x)

\frac{\partial}{\partial x} (2 x y - 4 x)

2 y - 4

Solution steps

\frac{\partial}{\partial x} (2 x y - 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (4 x) = 4

= 2 y - 4

n = 0 \sum \infty e^{- n}

\int 2 y^{2} d y

\int (\frac{x + 1}{( x - 3 ) ^{2}}) d x

\frac{\partial}{\partial z} (x yz)

\int (\frac{3}{x} - \frac{x}{3}) d x

What is (\partial)/(\partial x)(2xy-4x) ?
The answer to (\partial)/(\partial x)(2xy-4x) is 2y-4