en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of sqrt(2x^2-x)

Solution

\frac{d}{d x} (2 x^{2} - x)

Solution

\frac{4 x - 1}{2 2 x ^{2} - x}

Solution steps

\frac{d}{d x} (2 x^{2} - x)

Apply the chain rule:

\frac{1}{2 2 x ^{2} - x} \frac{d}{d x} (2 x^{2} - x)

= \frac{1}{2 2 x ^{2} - x} \frac{d}{d x} (2 x^{2} - x)

\frac{d}{d x} (2 x^{2} - x) = 4 x - 1

= \frac{1}{2 2 x ^{2} - x} (4 x - 1)

Simplify

\frac{1}{2 2 x ^{2} - x} (4 x - 1) : \frac{4 x - 1}{2 2 x ^{2} - x}

= \frac{4 x - 1}{2 2 x ^{2} - x}

Popular Examples

inverse oflaplace (2s+16)/(s^2+4s+13)inverse laplace

\frac{2 s + 16}{s ^{2} + 4 s + 13}

-18x^2y^{''}+4x(x+9)y^'-4(x+9)y=-4x^3

- 18 x^{2} y^{^{''}} + 4 x (x + 9) y^{^{'}} - 4 (x + 9) y = - 4 x^{3}

limit as x approaches 9 of sqrt(x)

x \to 9 lim (x)

integral of x/(25+x^2)

\int \frac{x}{25 + x ^{2}} d x

limit as x approaches 4 of e^4+4

x \to 4 lim (e^{4} + 4)

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(2x^2-x) ?
The derivative of sqrt(2x^2-x) is (4x-1)/(2sqrt(2x^2-x))
What is the first derivative of sqrt(2x^2-x) ?
The first derivative of sqrt(2x^2-x) is (4x-1)/(2sqrt(2x^2-x))