What is the derivative of e^{2x^{2x}} ?

The derivative of e^{2x^{2x}} is e^{2x^{2x}}*4x^{2x}(ln(x)+1)

What is the first derivative of e^{2x^{2x}} ?

The first derivative of e^{2x^{2x}} is e^{2x^{2x}}*4x^{2x}(ln(x)+1)

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derivative of

e^{2 x^{2 x}}

e^{2 x^{2 x}} \cdot 4 x^{2 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (e^{2 x^{2 x}})

Apply the chain rule:

e^{2 x^{2 x}} \frac{d}{d x} (2 x^{2 x})

= e^{2 x^{2 x}} \frac{d}{d x} (2 x^{2 x})

\frac{d}{d x} (2 x^{2 x}) = 4 x^{2 x} (ln (x) + 1)

= e^{2 x^{2 x}} \cdot 4 x^{2 x} (ln (x) + 1)

x \to 1 lim ((x - 1)^{- 1})

f (x) = cos^{3} (x), at (0)

\frac{\partial}{\partial x} (\frac{x - 2 y}{x + 2})

n = 1 \sum \infty \frac{4 n}{7 n + 1}

n = 1 \sum \infty 2^{n - 1}

What is the derivative of e^{2x^{2x}} ?
The derivative of e^{2x^{2x}} is e^{2x^{2x}}*4x^{2x}(ln(x)+1)
What is the first derivative of e^{2x^{2x}} ?
The first derivative of e^{2x^{2x}} is e^{2x^{2x}}*4x^{2x}(ln(x)+1)