What is area-x^2-1,x^2+4,[-2,3] ?

The answer to area-x^2-1,x^2+4,[-2,3] is 145/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area-x^2-1,x^2+4,[-2,3]

area

- x^{2} - 1, x^{2} + 4, [- 2, 3]

\frac{145}{3}

Decimal Notation

48.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} 2 x^{2} + 5 d x

Solve

\int_{- 2}^{3} 2 x^{2} + 5 d x : \frac{145}{3}

The area is:

= \frac{145}{3}

y^{^{'}} = x (1 + y)

\frac{\partial}{\partial x} (t x)

\int - \frac{1}{2} x d x

\int \frac{x ^{3}}{6} d x

y = \frac{9000}{x ^{2}}

What is area-x^2-1,x^2+4,[-2,3] ?
The answer to area-x^2-1,x^2+4,[-2,3] is 145/3