What is the sum from n=0 to infinity of (6/5)^n ?

The sum from n=0 to infinity of (6/5)^n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (6/5)^n

n = 0 \sum \infty (\frac{6}{5})^{n}

diverges

Solution steps

n = 0 \sum \infty (\frac{6}{5})^{n}

Apply Series Geometric Test:

diverges

= diverges

f (x) = x^{3} - x

\int 4 t^{3} cos (t^{4} + 1) d t

\frac{1}{arctan ( x )}

\int (x^{2} + 5)^{3} x d x

5 - 2 x

What is the sum from n=0 to infinity of (6/5)^n ?
The sum from n=0 to infinity of (6/5)^n is diverges