What is the d/(dy)(cos(x^2y)) ?

The d/(dy)(cos(x^2y)) is -sin(x^2y)x^2

What is the first d/(dy)(cos(x^2y)) ?

The first d/(dy)(cos(x^2y)) is -sin(x^2y)x^2

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\frac{d}{d y} (cos (x^{2} y))

- sin (x^{2} y) x^{2}

Solution steps

\frac{d}{d y} (cos (x^{2} y))

Treat

x

as a constant

Apply the chain rule:

- sin (x^{2} y) \frac{d}{d y} (x^{2} y)

= - sin (x^{2} y) \frac{d}{d y} (x^{2} y)

\frac{d}{d y} (x^{2} y) = x^{2}

= - sin (x^{2} y) x^{2}

n = 2 \sum \infty \frac{ln ^{2} ( n )}{n}

\int_{0}^{x} \frac{2}{1 + t} d t

\frac{d}{d x} (cos^{3} (5 x + 1))

y^{^{''}} + 4 y = - 6, y (\frac{π}{8}) = - 12, y^{^{'}} (\frac{π}{8}) = 2

\frac{d}{d x} ((x - 1) e^{- x})

What is the d/(dy)(cos(x^2y)) ?
The d/(dy)(cos(x^2y)) is -sin(x^2y)x^2
What is the first d/(dy)(cos(x^2y)) ?
The first d/(dy)(cos(x^2y)) is -sin(x^2y)x^2