What is the limit as h approaches 0 of 48+12h+h^2 ?

The limit as h approaches 0 of 48+12h+h^2 is 48

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limit as h approaches 0 of 48+12h+h^2

h \to 0 lim (48 + 12 h + h^{2})

48

Solution steps

h \to 0 lim (48 + 12 h + h^{2})

Plug in the value

h = 0

= 48 + 12 \cdot 0 + 0^{2}

Simplify

= 48

y = \frac{2 x - 1}{3 x + 5}

n = 1 \sum \infty \frac{6}{( - 5 ) ^{n}}

y^{^{''}} + 256 y = sec (16 x), y (0) = - 5, y^{^{'}} (0) = - 6

\int \frac{cos ( 5 x )}{3 + sin ( 5 x )} d x

y^{^{''}} + 25 y = 5 (csc (5 t))^{2}

What is the limit as h approaches 0 of 48+12h+h^2 ?
The limit as h approaches 0 of 48+12h+h^2 is 48