What is the derivative of (x^2-1^2) ?

The derivative of (x^2-1^2) is 4x(x^2-1)

What is the first derivative of (x^2-1^2) ?

The first derivative of (x^2-1^2) is 4x(x^2-1)

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\frac{d}{d x} ((x^{2} - 1)^{2})

4 x (x^{2} - 1)

Solution steps

\frac{d}{d x} ((x^{2} - 1)^{2})

Apply the chain rule:

2 (x^{2} - 1) \frac{d}{d x} (x^{2} - 1)

= 2 (x^{2} - 1) \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= 2 (x^{2} - 1) \cdot 2 x

Simplify

= 4 x (x^{2} - 1)

(e^{x} ln (y)) d x + (\frac{e ^{2 x}}{2 y}) d y = 0, y (0) = e

h (x) = \frac{6}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}}

y^{^{''}} - 4 y = 0, y (2) = 2, y^{^{'}} (- 1) = 1

x y^{^{'}} - 4 y = 3 x

- 8 t^{6}

What is the derivative of (x^2-1^2) ?
The derivative of (x^2-1^2) is 4x(x^2-1)
What is the first derivative of (x^2-1^2) ?
The first derivative of (x^2-1^2) is 4x(x^2-1)