What is the limit as θ approaches infinity of e^{-3θ}cos(θ) ?

The limit as θ approaches infinity of e^{-3θ}cos(θ) is 0

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limit as θ approaches infinity of e^{-3θ}cos(θ)

θ \to \infty lim (e^{- 3 θ} cos (θ))

0

Solution steps

θ \to \infty lim (e^{- 3 θ} cos (θ))

Apply the Squeeze Theorem:

0

= 0

h \to 0 lim (\frac{( a ^{u + h} - a ^{u} )}{h})

\int e^{- a x} sin (b x) d x

\int (e^{3 x} + 5 e^{- x}) d x

\frac{d}{d x} (c_{1} cos (x) + c_{2} sin (x))

\int sin (p) d p

What is the limit as θ approaches infinity of e^{-3θ}cos(θ) ?
The limit as θ approaches infinity of e^{-3θ}cos(θ) is 0