What is the solution for y^{''}-4y^'+4y=0 ?

The solution for y^{''}-4y^'+4y=0 is y=c_{1}e^{2t}+c_{2}te^{2t}

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y^{''}-4y^'+4y=0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0

y = c_{1} e^{2 t} + c_{2} t e^{2 t}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} t e^{2 t}

y = c_{1} e^{2 t} + c_{2} t e^{2 t}

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What is the solution for y^{''}-4y^'+4y=0 ?
The solution for y^{''}-4y^'+4y=0 is y=c_{1}e^{2t}+c_{2}te^{2t}