What is the solution for (dQ)/(dt)=-5/(980-\frac{3t){10}}Q+14.1 ?

The solution for (dQ)/(dt)=-5/(980-\frac{3t){10}}Q+14.1 is Q=0.3(-3t+9800)+c_{1}(9800-3t)^{50/3}

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(dQ)/(dt)=-5/(980-\frac{3t){10}}Q+14.1

\frac{d Q}{d t} = - \frac{5}{980 - \frac{3 t}{10}} Q + 14.1

Q = 0.3 (- 3 t + 9800) + c_{1} (9800 - 3 t)^{\frac{50}{3}}

Solution steps

\frac{d Q}{d t} = - \frac{5}{980 - \frac{3 t}{10}} Q + 14.1

Solve linear ODE:

Q = 0.3 (- 3 t + 9800) + c_{1} (9800 - 3 t)^{\frac{50}{3}}

Q = 0.3 (- 3 t + 9800) + c_{1} (9800 - 3 t)^{\frac{50}{3}}

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What is the solution for (dQ)/(dt)=-5/(980-\frac{3t){10}}Q+14.1 ?
The solution for (dQ)/(dt)=-5/(980-\frac{3t){10}}Q+14.1 is Q=0.3(-3t+9800)+c_{1}(9800-3t)^{50/3}