What is the derivative of ln(4z+1) ?

The derivative of ln(4z+1) is 4/(4z+1)

What is the first derivative of ln(4z+1) ?

The first derivative of ln(4z+1) is 4/(4z+1)

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derivative of

ln (4 z + 1)

\frac{4}{4 z + 1}

Solution steps

\frac{d}{d z} (ln (4 z + 1))

Apply the chain rule:

\frac{1}{4 z + 1} \frac{d}{d z} (4 z + 1)

= \frac{1}{4 z + 1} \frac{d}{d z} (4 z + 1)

\frac{d}{d z} (4 z + 1) = 4

= \frac{1}{4 z + 1} \cdot 4

Simplify

\frac{1}{4 z + 1} \cdot 4 : \frac{4}{4 z + 1}

= \frac{4}{4 z + 1}

x \to 1 lim (3 x^{3} - 4 x^{2} + x + 5)

\frac{d}{d x} (sin (x) + \frac{8}{7} cot (x))

\int_{- 1}^{0} (2 x + 3)^{2} d x

\int e^{\frac{1}{x}} \frac{1}{x ^{3}} d x

y^{^{''}} - 4 y^{^{'}} + 3 y = t^{2}

What is the derivative of ln(4z+1) ?
The derivative of ln(4z+1) is 4/(4z+1)
What is the first derivative of ln(4z+1) ?
The first derivative of ln(4z+1) is 4/(4z+1)