What is the first derivative of x^2-3 ?

The first derivative of x^2-3 is 2x

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derivative of x^2-3

derivative of

x^{2} - 3

2 x

Solution steps

\frac{d}{d x} (x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= 2 x - 0

Simplify

= 2 x

y^{^{'}} + \frac{1}{x} y = \frac{1}{x ^{2}}

ln (3 x - 2)

\int \frac{3}{x} d x

ln (\frac{4 x - 4}{5 x + 9})

x y^{^{'}} - 3 y = 6