What is the integral from-2 to 0 of sqrt(1+(-4)^2) ?

The integral from-2 to 0 of sqrt(1+(-4)^2) is 2sqrt(17)

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integral from-2 to 0 of sqrt(1+(-4)^2)

\int_{- 2}^{0} 1 + (- 4)^{2} d x

217

Decimal Notation

8.24621 \dots

Solution steps

\int_{- 2}^{0} 1 + (- 4)^{2} d x

Integral of a constant:

\int a d x = a x

= [1 + (- 4)^{2} x]_{- 2}^{0}

1 + (- 4)^{2} = 17

= [17 x]_{- 2}^{0}

Compute the boundaries:

217

= 217

y = cos (cos (cos (x)))

\frac{\partial}{\partial x} (9 + x ln (x y - 7))

- x^{2} - 3 x, [- 4, 4]

\int \frac{x + 8}{x} d x

\int \frac{1}{( x + 1 ) ^{4}} d x

What is the integral from-2 to 0 of sqrt(1+(-4)^2) ?
The integral from-2 to 0 of sqrt(1+(-4)^2) is 2sqrt(17)