What is the integral of-3/y ?

The integral of-3/y is -3ln|y|+C

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integral of-3/y

\int - \frac{3}{y} d y

- 3 ln ∣ y ∣ + C

Solution steps

\int - \frac{3}{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= - 3 ln ∣ y ∣

Add a constant to the solution

= - 3 ln ∣ y ∣ + C

\frac{\partial}{\partial x} (\frac{x - y}{x + y} - y^{3})

\frac{3}{( s + 1 ) ^{2} + 9}

\frac{d}{d x} (tan (13 x))

2 e^{4 x} cos (5 x)

\frac{\partial}{\partial x} (ln (x^{7} - y^{3}))