What is the derivative of-5/(\sqrt[3]{x}) ?

The derivative of-5/(\sqrt[3]{x}) is 5/(3x^{4/3)}

What is the first derivative of-5/(\sqrt[3]{x}) ?

The first derivative of-5/(\sqrt[3]{x}) is 5/(3x^{4/3)}

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\frac{5}{3 x ^{\frac{4}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 5 \frac{d}{d x} (x^{- \frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 5 (- \frac{1}{3} x^{- \frac{1}{3} - 1})

Simplify

- 5 (- \frac{1}{3} x^{- \frac{1}{3} - 1}) : \frac{5}{3 x ^{\frac{4}{3}}}

= \frac{5}{3 x ^{\frac{4}{3}}}

f (x) = e^{\frac{a}{x}}

\int \frac{- 2 x ^{4}}{( 1 - x ) ^{3}} d x

sin (x^{3})

f (t) = 2 t

\frac{d}{d z} (\frac{sin ( z )}{( z + 1 ) ^{2}})

What is the derivative of-5/(\sqrt[3]{x}) ?
The derivative of-5/(\sqrt[3]{x}) is 5/(3x^{4/3)}
What is the first derivative of-5/(\sqrt[3]{x}) ?
The first derivative of-5/(\sqrt[3]{x}) is 5/(3x^{4/3)}