What is the tangent of y=(5x)/(x-3),(4,20) ?

The tangent of y=(5x)/(x-3),(4,20) is y=-15x+80

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tangent of y=(5x)/(x-3),(4,20)

tangent of

y = \frac{5 x}{x - 3}, (4, 20)

y = - 15 x + 80

Solution steps

Find the slope of

y = \frac{5 x}{x - 3} : \frac{d y}{d x} = - \frac{15}{( x - 3 ) ^{2}}

Compute the slope of

y = \frac{5 x}{x - 3}

(4, 20) : m = - 15

Find the line with slope m=

- 15

and passing through

(4, 20) : y = - 15 x + 80

y = - 15 x + 80

\int (x^{2} + 2 y) d x

x - 2, 14 - x, 2

\int (1 - x) cos (nπ x) d x

\frac{5 s}{s ^{2} + 4}

\frac{\partial}{\partial y} (x y - x^{2} - y^{2})

What is the tangent of y=(5x)/(x-3),(4,20) ?
The tangent of y=(5x)/(x-3),(4,20) is y=-15x+80