What is the tangent of f(x)=2x^2+3x-2,\at x=-2 ?

The tangent of f(x)=2x^2+3x-2,\at x=-2 is y=-5x-10

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tangent of f(x)=2x^2+3x-2,\at x=-2

tangent of

f (x) = 2 x^{2} + 3 x - 2, at x = - 2

y = - 5 x - 10

Solution steps

Find the tangent point:

(- 2, 0)

Find the slope of

f (x) = 2 x^{2} + 3 x - 2 : \frac{df ( x )}{d x} = 4 x + 3

Compute the slope of

f (x) = 2 x^{2} + 3 x - 2

x = - 2 : m = - 5

Find the line with slope m=

- 5

and passing through

(- 2, 0) : y = - 5 x - 10

y = - 5 x - 10

\frac{x}{1 + x ^{2}}, at x = 2

\frac{d}{d x} (arctan (e^{- 2 x}))

6 x - 2, x^{2} + 2 x + 2, 1

(- 1, 3), (- 6, - 2)

\int (2 + cos (2 x))^{2} d x

What is the tangent of f(x)=2x^2+3x-2,\at x=-2 ?
The tangent of f(x)=2x^2+3x-2,\at x=-2 is y=-5x-10