What is the derivative of 3e^x+(x-2^2) ?

The derivative of 3e^x+(x-2^2) is 3e^x+2(x-2)

What is the first derivative of 3e^x+(x-2^2) ?

The first derivative of 3e^x+(x-2^2) is 3e^x+2(x-2)

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\frac{d}{d x} (3 e^{x} + (x - 2)^{2})

3 e^{x} + 2 (x - 2)

Solution steps

\frac{d}{d x} (3 e^{x} + (x - 2)^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 e^{x}) + \frac{d}{d x} ((x - 2)^{2})

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

\frac{d}{d x} ((x - 2)^{2}) = 2 (x - 2)

= 3 e^{x} + 2 (x - 2)

x \to 6 lim (5)

y^{^{''}} + 10 y^{^{'}} + 25 y = 7 e^{2 x}

\int_{- \infty}^{3} x e^{x} d x

5 e^{x} cos (x) (0.5)

\int x sin (7 x) d x

What is the derivative of 3e^x+(x-2^2) ?
The derivative of 3e^x+(x-2^2) is 3e^x+2(x-2)
What is the first derivative of 3e^x+(x-2^2) ?
The first derivative of 3e^x+(x-2^2) is 3e^x+2(x-2)