What is the tangent of f(x)= 2/(3x+5),(-1,1) ?

The tangent of f(x)= 2/(3x+5),(-1,1) is y=-3/2 x-1/2

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tangent of f(x)= 2/(3x+5),(-1,1)

tangent of

f (x) = \frac{2}{3 x + 5}, (- 1, 1)

y = - \frac{3}{2} x - \frac{1}{2}

Solution steps

Find the slope of

f (x) = \frac{2}{3 x + 5} : \frac{df ( x )}{d x} = - \frac{6}{( 3 x + 5 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{3 x + 5}

(- 1, 1) : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- 1, 1) : y = - \frac{3}{2} x - \frac{1}{2}

y = - \frac{3}{2} x - \frac{1}{2}

x \to 0 lim (\frac{x ^{2} + 7 x}{x})

\int (2 t + 3)^{- 3} d t

f (x) = \frac{2 x - 1}{x + 5}, at x = 4

\int \frac{x ^{2} + 9}{x ^{4}} d x

sin (5 x)

What is the tangent of f(x)= 2/(3x+5),(-1,1) ?
The tangent of f(x)= 2/(3x+5),(-1,1) is y=-3/2 x-1/2