What is the solution for (dy)/(dx)=(y-x+5)/(2y-2x+6) ?

The solution for (dy)/(dx)=(y-x+5)/(2y-2x+6) is y=x+2\W(-1/(2e^{(x+c_{1))/4}})-1

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(dy)/(dx)=(y-x+5)/(2y-2x+6)

\frac{d y}{d x} = \frac{y - x + 5}{2 y - 2 x + 6}

y = x + 2 W (- \frac{1}{2 e ^{\frac{x + c _{1}}{4}}}) - 1

Solution steps

\frac{d y}{d x} = \frac{y - x + 5}{2 y - 2 x + 6}

Solve using substitution:

y = x + 2 W (- \frac{1}{2 e ^{\frac{x + c _{1}}{4}}}) - 1

y = x + 2 W (- \frac{1}{2 e ^{\frac{x + c _{1}}{4}}}) - 1

\int \frac{1}{x x ^{6} - 4} d x

x \frac{d y}{d x} = y + x^{2} + y^{2}, x > 0

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\int_{0}^{2} (4 - x)^{2} d x

\frac{- 2 x - y}{x + 3 y ^{2}}

What is the solution for (dy)/(dx)=(y-x+5)/(2y-2x+6) ?
The solution for (dy)/(dx)=(y-x+5)/(2y-2x+6) is y=x+2\W(-1/(2e^{(x+c_{1))/4}})-1