What is the tangent of 1/(2-3x),\at x=1 ?

The tangent of 1/(2-3x),\at x=1 is y=3x-4

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tangent of 1/(2-3x),\at x=1

tangent of

\frac{1}{2 - 3 x}, at x = 1

y = 3 x - 4

Solution steps

Find the tangent point:

(1, - 1)

Find the slope of

y = \frac{1}{2 - 3 x} : \frac{d y}{d x} = \frac{3}{( 2 - 3 x ) ^{2}}

Compute the slope of

y = \frac{1}{2 - 3 x}

x = 1 : m = 3

Find the line with slope m=

3

and passing through

(1, - 1) : y = 3 x - 4

y = 3 x - 4

(cosh (t))^{^{'}}

\frac{x}{9 + x ^{2}}

\frac{d y}{d x} = - \frac{1}{x + 2}

x \to 3 lim (x (x - 1))

\int \frac{5 e ^{x}}{e ^{2 x} + 4 e ^{x} + 4} d x

What is the tangent of 1/(2-3x),\at x=1 ?
The tangent of 1/(2-3x),\at x=1 is y=3x-4