What is the limit as x approaches 0 of 1/(x^3-1)+1 ?

The limit as x approaches 0 of 1/(x^3-1)+1 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/(x^3-1)+1

x \to 0 lim (\frac{1}{x ^{3} - 1} + 1)

0

Solution steps

x \to 0 lim (\frac{1}{x ^{3} - 1} + 1)

Plug in the value

x = 0

= \frac{1}{0 ^{3} - 1} + 1

Simplify

\frac{1}{0 ^{3} - 1} + 1 : 0

= 0

x \to 0 lim (\frac{x ^{2} - 5}{x})

t \to - 2 lim (t^{2} + 5 t + 7)

\int tan^{3} (\frac{x}{2}) sec^{3} (\frac{x}{2}) d x

f^{^{'}} (x) = \frac{2 x ^{2} - 9 x + 8}{6 x + 5}

\int r^{3} + 2 r d r

What is the limit as x approaches 0 of 1/(x^3-1)+1 ?
The limit as x approaches 0 of 1/(x^3-1)+1 is 0