What is the limit as x approaches 0+of (7x)^x ?

The limit as x approaches 0+of (7x)^x is 1

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limit as x approaches 0+of (7x)^x

x \to 0 + lim ((7 x)^{x})

1

Solution steps

x \to 0 + lim ((7 x)^{x})

Simplify

(7 x)^{x} : 7^{x} x^{x}

= x \to 0 + lim (7^{x} x^{x})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (7^{x}) \cdot x \to 0 + lim (x^{x})

x \to 0 + lim (7^{x}) = 1

x \to 0 + lim (x^{x}) = 1

= 1 \cdot 1

Simplify

= 1

f (x) = 2 x^{2} - 4 x, at x = - 1

f (x) = 4 x - x^{2}, (2, 5)

\int (2 x - 5)^{11} d x

\int_{- 1}^{2} \frac{x}{( x + 1 ) ^{2}} d x

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What is the limit as x approaches 0+of (7x)^x ?
The limit as x approaches 0+of (7x)^x is 1