What is the derivative of f(x)=(3x^2-x+5)(x^2+3x-9) ?

The derivative of f(x)=(3x^2-x+5)(x^2+3x-9) is 12x^3+24x^2-50x+24

What is the first derivative of f(x)=(3x^2-x+5)(x^2+3x-9) ?

The first derivative of f(x)=(3x^2-x+5)(x^2+3x-9) is 12x^3+24x^2-50x+24

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derivative of

f (x) = (3 x^{2} - x + 5) (x^{2} + 3 x - 9)

12 x^{3} + 24 x^{2} - 50 x + 24

Solution steps

\frac{d}{d x} ((3 x^{2} - x + 5) (x^{2} + 3 x - 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x^{2} - x + 5, g = x^{2} + 3 x - 9

= \frac{d}{d x} (3 x^{2} - x + 5) (x^{2} + 3 x - 9) + \frac{d}{d x} (x^{2} + 3 x - 9) (3 x^{2} - x + 5)

\frac{d}{d x} (3 x^{2} - x + 5) = 6 x - 1

\frac{d}{d x} (x^{2} + 3 x - 9) = 2 x + 3

= (6 x - 1) (x^{2} + 3 x - 9) + (2 x + 3) (3 x^{2} - x + 5)

Simplify

(6 x - 1) (x^{2} + 3 x - 9) + (2 x + 3) (3 x^{2} - x + 5) : 12 x^{3} + 24 x^{2} - 50 x + 24

= 12 x^{3} + 24 x^{2} - 50 x + 24

x \to 2 + lim (\frac{- 2}{x ^{2} - 4})

x \to 0 lim (- \frac{3}{x ^{2}})

arctan (sin (4 x))

y^{^{''}} + 25 y = - 25 sec^{2} (5 x)

\frac{\partial}{\partial x} (2 + x ln (x y - 7))

What is the derivative of f(x)=(3x^2-x+5)(x^2+3x-9) ?
The derivative of f(x)=(3x^2-x+5)(x^2+3x-9) is 12x^3+24x^2-50x+24
What is the first derivative of f(x)=(3x^2-x+5)(x^2+3x-9) ?
The first derivative of f(x)=(3x^2-x+5)(x^2+3x-9) is 12x^3+24x^2-50x+24