What is the first derivative of 3x-8 ?

The first derivative of 3x-8 is 3

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derivative of 3x-8

derivative of

3 x - 8

3

Solution steps

\frac{d}{d x} (3 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (8)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (8) = 0

= 3 - 0

Simplify

= 3

(5 y - 2 x) y^{^{'}} - 2 y = 0

f (x) = x x^{2} + 60, at x = 2

\frac{\partial}{\partial x} ((3 - x) (3 - y) (x + y - 3))

\frac{d ^{2}}{d x ^{2}} ((3 + 2 x) e^{- 3 x})

x (- 3 x^{- 4})