What is the solution for y^{''}+6y^'+34y=0,y(0)=-1,y^'(0)=13 ?

The solution for y^{''}+6y^'+34y=0,y(0)=-1,y^'(0)=13 is y=e^{-3t}(-cos(5t)+2sin(5t))

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y^{''}+6y^'+34y=0,y(0)=-1,y^'(0)=13

y^{^{''}} + 6 y^{^{'}} + 34 y = 0, y (0) = - 1, y^{^{'}} (0) = 13

y = e^{- 3 t} (- cos (5 t) + 2 sin (5 t))

Solution steps

y^{''} (t) + 6 y^{'} (t) + 34 y = 0

Solve linear ODE:

y = e^{- 3 t} (- cos (5 t) + 2 sin (5 t))

y = e^{- 3 t} (- cos (5 t) + 2 sin (5 t))

f (x) = \frac{28}{x}

x \to 1 lim (2 x + 1)

x \to 0 - lim (\frac{e ^{\frac{1}{x}}}{x})

\int_{- π}^{π} sin (m x) cos (n x) d x

9 e^{x} x

What is the solution for y^{''}+6y^'+34y=0,y(0)=-1,y^'(0)=13 ?
The solution for y^{''}+6y^'+34y=0,y(0)=-1,y^'(0)=13 is y=e^{-3t}(-cos(5t)+2sin(5t))