What is the derivative of 4x^3+3x^2+2x ?

The derivative of 4x^3+3x^2+2x is 12x^2+6x+2

What is the first derivative of 4x^3+3x^2+2x ?

The first derivative of 4x^3+3x^2+2x is 12x^2+6x+2

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\frac{d}{d x} (4 x^{3} + 3 x^{2} + 2 x)

12 x^{2} + 6 x + 2

Solution steps

\frac{d}{d x} (4 x^{3} + 3 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 12 x^{2} + 6 x + 2

\frac{d}{d x} (x^{3} - 100 x + 1)

\frac{d ^{2}}{d x ^{2}} (e^{7 x - 4})

\int arctan (2 t) d t

f (x) = x^{4} - 8 x^{3}

f (x) = 3 x^{3} - 9 x

What is the derivative of 4x^3+3x^2+2x ?
The derivative of 4x^3+3x^2+2x is 12x^2+6x+2
What is the first derivative of 4x^3+3x^2+2x ?
The first derivative of 4x^3+3x^2+2x is 12x^2+6x+2