What is the derivative of (x^2+y^2^6) ?

The derivative of (x^2+y^2^6) is 6(x^2+y^2)^5(2x+2y(dy)/(dx))

What is the first derivative of (x^2+y^2^6) ?

The first derivative of (x^2+y^2^6) is 6(x^2+y^2)^5(2x+2y(dy)/(dx))

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\frac{d}{d x} ((x^{2} + y^{2})^{6})

6 (x^{2} + y^{2})^{5} (2 x + 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} ((x^{2} + y^{2})^{6})

Apply the chain rule:

6 (x^{2} + y^{2})^{5} \frac{d}{d x} (x^{2} + y^{2})

= 6 (x^{2} + y^{2})^{5} \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= 6 (x^{2} + y^{2})^{5} (2 x + 2 y \frac{d y}{d x})

\frac{\partial}{\partial v} (\frac{u + v}{2})

y^{^{''''}} - 9 y^{^{''}} + 20 y = 0

\int_{0}^{3} 1 + 16 x^{2} d x

x^{2}

What is the derivative of (x^2+y^2^6) ?
The derivative of (x^2+y^2^6) is 6(x^2+y^2)^5(2x+2y(dy)/(dx))
What is the first derivative of (x^2+y^2^6) ?
The first derivative of (x^2+y^2^6) is 6(x^2+y^2)^5(2x+2y(dy)/(dx))