What is the integral of 4/(x^2)-7/(x^5) ?

The integral of 4/(x^2)-7/(x^5) is -4/x+7/(4x^4)+C

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integral of 4/(x^2)-7/(x^5)

\int \frac{4}{x ^{2}} - \frac{7}{x ^{5}} d x

- \frac{4}{x} + \frac{7}{4 x ^{4}} + C

Solution steps

\int \frac{4}{x ^{2}} - \frac{7}{x ^{5}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{x ^{2}} d x - \int \frac{7}{x ^{5}} d x

\int \frac{4}{x ^{2}} d x = - \frac{4}{x}

\int \frac{7}{x ^{5}} d x = - \frac{7}{4 x ^{4}}

= - \frac{4}{x} - (- \frac{7}{4 x ^{4}})

Simplify

= - \frac{4}{x} + \frac{7}{4 x ^{4}}

Add a constant to the solution

= - \frac{4}{x} + \frac{7}{4 x ^{4}} + C

f (x) = x^{3} + 7 x - 7, (1, 1)

y^{^{''''}} = 0

y^{^{''}} - 6 y^{^{'}} + 25 y = 64 e^{- t}

\int 2 (x + 2)^{3} d x

\frac{\partial}{\partial x} (x^{3} + 3 x y^{2} - 15 x - 12 y)

What is the integral of 4/(x^2)-7/(x^5) ?
The integral of 4/(x^2)-7/(x^5) is -4/x+7/(4x^4)+C