What is (\partial)/(\partial x)(x^2+xln(yz)) ?

The answer to (\partial)/(\partial x)(x^2+xln(yz)) is 2x+ln(yz)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2+xln(yz))

\frac{\partial}{\partial x} (x^{2} + x ln (yz))

2 x + ln (yz)

Solution steps

\frac{\partial}{\partial x} (x^{2} + x ln (yz))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x ln (yz))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x ln (yz)) = ln (yz)

= 2 x + ln (yz)

x \to 0 lim (ln (\frac{x}{x + 1}))

\int 2^{1 - x} d x

n = 1 \sum \infty \frac{n}{4 ^{n}}

\frac{d}{d x} (6 x - 4)

y^{^{''}} + y^{^{'}} + y = x e^{x} + e^{- x} (1 + 2 x)

What is (\partial)/(\partial x)(x^2+xln(yz)) ?
The answer to (\partial)/(\partial x)(x^2+xln(yz)) is 2x+ln(yz)