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Popular >

derivative of 1/4 x^3+x-1

Solution

\frac{d}{d x} (\frac{1}{4} x^{3} + x - 1)

Solution

\frac{3 x ^{2}}{4} + 1

Solution steps

\frac{d}{d x} (\frac{1}{4} x^{3} + x - 1)

Simplify

\frac{1}{4} x^{3} + x - 1 : \frac{x ^{3}}{4} + x - 1

= \frac{d}{d x} (\frac{x ^{3}}{4} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{4}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x ^{3}}{4}) = \frac{3 x ^{2}}{4}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{3 x ^{2}}{4} + 1 - 0

Simplify

= \frac{3 x ^{2}}{4} + 1

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\int (cos (x)) (sin (x)) d x

Frequently Asked Questions (FAQ)

What is the derivative of 1/4 x^3+x-1 ?
The derivative of 1/4 x^3+x-1 is (3x^2)/4+1
What is the first derivative of 1/4 x^3+x-1 ?
The first derivative of 1/4 x^3+x-1 is (3x^2)/4+1