What is the derivative of f(x)=2^{2x} ?

The derivative of f(x)=2^{2x} is ln(2)*2^{2x+1}

What is the first derivative of f(x)=2^{2x} ?

The first derivative of f(x)=2^{2x} is ln(2)*2^{2x+1}

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derivative of

f (x) = 2^{2 x}

ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (2^{2 x})

Simplify

2^{2 x} : 4^{x}

= \frac{d}{d x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{x} ln (4)

Simplify

4^{x} ln (4) : ln (2) \cdot 2^{2 x + 1}

= ln (2) \cdot 2^{2 x + 1}

\int_{1}^{5} 2 r^{2} ln (r) d r

\frac{d}{d x} (ln (x^{2} + 4 x))

y = x, y = 2 - x, y = 0

y = 2 sin (x), y = e^{x}, x = 0, x = \frac{π}{2}

y^{^{'}} = x^{2} - 3 y

What is the derivative of f(x)=2^{2x} ?
The derivative of f(x)=2^{2x} is ln(2)*2^{2x+1}
What is the first derivative of f(x)=2^{2x} ?
The first derivative of f(x)=2^{2x} is ln(2)*2^{2x+1}