What is the solution for 16y^{''}+11y=0 ?

The solution for 16y^{''}+11y=0 is y=c_{1}cos((sqrt(11)t)/4)+c_{2}sin((sqrt(11)t)/4)

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16y^{''}+11y=0

16 y^{^{''}} + 11 y = 0

y = c_{1} cos (\frac{11 t}{4}) + c_{2} sin (\frac{11 t}{4})

Solution steps

16 y^{''} (t) + 11 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{11 t}{4}) + c_{2} sin (\frac{11 t}{4})

y = c_{1} cos (\frac{11 t}{4}) + c_{2} sin (\frac{11 t}{4})

\int \frac{e ^{2 x}}{e ^{x} - 1} d x

\int_{0}^{1} \frac{x}{1 + x ^{2}} d x

4 cos (x)

n = 1 \sum \infty (- 1)^{n} n^{- 2}

\frac{1}{( s + 1 ) ^{2} ( s ^{2} + 1 )}

What is the solution for 16y^{''}+11y=0 ?
The solution for 16y^{''}+11y=0 is y=c_{1}cos((sqrt(11)t)/4)+c_{2}sin((sqrt(11)t)/4)