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Popular >

integral of 1/(2+y)

Solution

\int \frac{1}{2 + y} d y

Solution

ln ∣ 2 + y ∣ + C

Solution steps

\int \frac{1}{2 + y} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 2 + y

= ln ∣ 2 + y ∣

Add a constant to the solution

= ln ∣ 2 + y ∣ + C

Popular Examples

integral of (-2x^3+12x^2-20x+8.5)

\int (- 2 x^{3} + 12 x^{2} - 20 x + 8.5) d x

limit as x approaches 2 of (x^2-2x)/x

x \to 2 lim (\frac{x ^{2} - 2 x}{x})

integral of x*sqrt(2*x-5)

\int x \cdot 2 \cdot x - 5 d x

(d^3)/(dx^3)(sqrt(2x+3))

\frac{d ^{3}}{d x ^{3}} (2 x + 3)

integral from 0 to 7 of 1/((49+x^2))

\int_{0}^{7} \frac{1}{( 49 + x ^{2} )} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(2+y) ?
The integral of 1/(2+y) is ln|2+y|+C