What is the derivative of y^2-x^2+2 ?

The derivative of y^2-x^2+2 is -2x+2y(dy)/(dx)

What is the first derivative of y^2-x^2+2 ?

The first derivative of y^2-x^2+2 is -2x+2y(dy)/(dx)

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\frac{d}{d x} (y^{2} - x^{2} + 2)

- 2 x + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (y^{2} - x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{2}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2) = 0

= 2 y \frac{d y}{d x} - 2 x + 0

Simplify

= - 2 x + 2 y \frac{d y}{d x}

\int e^{s i n (θ)} cos (θ) d θ

f (x) = \frac{5 x}{4 x ^{2} + 1}

\int \frac{x + 4}{x ^{2} + 1} d x

f (t) = t \cdot sin (3 t)

\int sinh (x) + C d x

What is the derivative of y^2-x^2+2 ?
The derivative of y^2-x^2+2 is -2x+2y(dy)/(dx)
What is the first derivative of y^2-x^2+2 ?
The first derivative of y^2-x^2+2 is -2x+2y(dy)/(dx)