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Popular >

y^'=(y+t^3)/t

Solution

y^{^{'}} = \frac{y + t ^{3}}{t}

Solution

y = \frac{t ^{3}}{2} + c_{1} t

Solution steps

y^{'} (t) = \frac{y + t ^{3}}{t}

Solve linear ODE:

y = \frac{t ^{3}}{2} + c_{1} t

y = \frac{t ^{3}}{2} + c_{1} t

Popular Examples

integral from 1 to 2 of 7/(x^3+3x)

\int_{1}^{2} \frac{7}{x ^{3} + 3 x} d x

y^{'''}+12y^{''}+36y^'=18x^2

y^{^{'''}} + 12 y^{^{''}} + 36 y^{^{'}} = 18 x^{2}

derivative of x^3+3 derivative of

x^{3} + 3

derivative of f(x)=(3+x^5)^{2/3}derivative of

f (x) = (3 + x^{5})^{\frac{2}{3}}

derivative of x^3cos(4x)derivative of

x^{3} cos (4 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y+t^3)/t ?
The solution for y^'=(y+t^3)/t is y=(t^3)/2+c_{1}t