What is derivative of f(x)=\sqrt[9]{t}-9e^t ?

The answer to derivative of f(x)=\sqrt[9]{t}-9e^t is (dt)/(dx)=0

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derivative of f(x)=\sqrt[9]{t}-9e^t

derivative of

\frac{d t}{d x} = 0

Solution steps

Treat

t

t (x)

Differentiate both sides:

0 = \frac{\frac{d t}{d x}}{9 t ^{\frac{8}{9}}} - e^{t} \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d y}{d t} = \frac{1}{t y + t + y + 1}

\int_{0}^{1} \frac{2 x}{( x ^{2} + 4 ) ^{3}} d x

4 - x, 0, 4

\int \frac{9 - x ^{2}}{x ^{2}} d x

\int (\frac{( ln ( x ) ) ^{2}}{x}) d x

What is derivative of f(x)=\sqrt[9]{t}-9e^t ?
The answer to derivative of f(x)=\sqrt[9]{t}-9e^t is (dt)/(dx)=0