What is the derivative of sqrt(x^2-x) ?

The derivative of sqrt(x^2-x) is (2x-1)/(2sqrt(x^2-x))

What is the first derivative of sqrt(x^2-x) ?

The first derivative of sqrt(x^2-x) is (2x-1)/(2sqrt(x^2-x))

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\frac{d}{d x} (x^{2} - x)

\frac{2 x - 1}{2 x ^{2} - x}

Solution steps

\frac{d}{d x} (x^{2} - x)

Apply the chain rule:

\frac{1}{2 x ^{2} - x} \frac{d}{d x} (x^{2} - x)

= \frac{1}{2 x ^{2} - x} \frac{d}{d x} (x^{2} - x)

\frac{d}{d x} (x^{2} - x) = 2 x - 1

= \frac{1}{2 x ^{2} - x} (2 x - 1)

Simplify

\frac{1}{2 x ^{2} - x} (2 x - 1) : \frac{2 x - 1}{2 x ^{2} - x}

= \frac{2 x - 1}{2 x ^{2} - x}

\int tan^{2} (x) d tan (x) d x

\int 25 - x^{2} d x

z \to 0 lim (\frac{8}{z ^{3}} + \frac{2}{z} + 2)

y = \frac{9}{x ^{2}}, y = 10 - x^{2}, y = 12

\frac{d y}{d x} - \frac{y}{2 x} = 3 x

What is the derivative of sqrt(x^2-x) ?
The derivative of sqrt(x^2-x) is (2x-1)/(2sqrt(x^2-x))
What is the first derivative of sqrt(x^2-x) ?
The first derivative of sqrt(x^2-x) is (2x-1)/(2sqrt(x^2-x))