What is the integral from 0 to 1.25 of 1000x ?

The integral from 0 to 1.25 of 1000x is 781.25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1.25 of 1000x

\int_{0}^{1.25} 1000 x d x

781.25

Solution steps

\int_{0}^{1.25} 1000 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1000 \cdot \int_{0}^{1.25} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1.25}

= 1000 [\frac{x ^{2}}{2}]_{0}^{1.25}

Simplify

= 1000 [0.5 x^{2}]_{0}^{1.25}

Compute the boundaries:

0.78125

= 1000 \cdot 0.78125

Simplify

= 781.25

y^{^{''}} + y^{^{'}} + 6 y = 0

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{8 + e ^{x}}

(4^{x})^{9}

\frac{d y}{d x}, 4^{x} = 2 x y

What is the integral from 0 to 1.25 of 1000x ?
The integral from 0 to 1.25 of 1000x is 781.25