What is the tangent of y=3x^2-6,(-1,-3) ?

The tangent of y=3x^2-6,(-1,-3) is y=-6x-9

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tangent of y=3x^2-6,(-1,-3)

tangent of

y = 3 x^{2} - 6, (- 1, - 3)

y = - 6 x - 9

Solution steps

Find the slope of

y = 3 x^{2} - 6 : \frac{d y}{d x} = 6 x

Compute the slope of

y = 3 x^{2} - 6

(- 1, - 3) : m = - 6

Find the line with slope m=

- 6

and passing through

(- 1, - 3) : y = - 6 x - 9

y = - 6 x - 9

\int_{2}^{\infty} e^{- 9 p} d p

\int 5^{x^{2} + 2 x + 3} (x + 1) d x

\int 5 x^{\frac{1}{4}} d x

\frac{s}{s ^{2} + \frac{1}{l c}}

x \to 2 lim (x^{2} f (x))

What is the tangent of y=3x^2-6,(-1,-3) ?
The tangent of y=3x^2-6,(-1,-3) is y=-6x-9