What is the derivative of y=-(2x^2)/(5y^2) ?

The derivative of y=-(2x^2)/(5y^2) is -(4x)/(5y^2)

What is the first derivative of y=-(2x^2)/(5y^2) ?

The first derivative of y=-(2x^2)/(5y^2) is -(4x)/(5y^2)

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derivative of

y = - \frac{2 x ^{2}}{5 y ^{2}}

- \frac{4 x}{5 y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{2 x ^{2}}{5 y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{2}{5 y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{2}{5 y ^{2}} \cdot 2 x^{2 - 1}

Simplify

- \frac{2}{5 y ^{2}} \cdot 2 x^{2 - 1} : - \frac{4 x}{5 y ^{2}}

= - \frac{4 x}{5 y ^{2}}

\frac{d}{d x} (8 e^{8 x})

sin (x) \cdot e^{x}

\frac{\partial}{\partial x} (- 3 x y (- 12 - x - y))

\frac{d}{d x} (- \frac{2}{3} x^{3})

\int_{- 1}^{4} (3 x^{2} + 8 x - 5) d x

What is the derivative of y=-(2x^2)/(5y^2) ?
The derivative of y=-(2x^2)/(5y^2) is -(4x)/(5y^2)
What is the first derivative of y=-(2x^2)/(5y^2) ?
The first derivative of y=-(2x^2)/(5y^2) is -(4x)/(5y^2)