What is the integral from 0 to 7 of x/(x^2-1) ?

The integral from 0 to 7 of x/(x^2-1) is diverges

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integral from 0 to 7 of x/(x^2-1)

\int_{0}^{7} \frac{x}{x ^{2} - 1} d x

diverges

Solution steps

\int_{0}^{7} \frac{x}{x ^{2} - 1} d x

Find undefined (singularity) points:

x = 1

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{1} \frac{x}{x ^{2} - 1} d x + \int_{1}^{7} \frac{x}{x ^{2} - 1} d x

\int_{0}^{1} \frac{x}{x ^{2} - 1} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

6 x e^{- x}

\int_{0}^{\frac{π}{4}} 8 sec^{3} (x) d x

\frac{t d Q}{d t} + Q = t^{4} ln (t)

\frac{d}{d x} (\frac{1}{e ^{x}})

f (x) = 2 x^{2} - 5 x + 1, at x = 2

What is the integral from 0 to 7 of x/(x^2-1) ?
The integral from 0 to 7 of x/(x^2-1) is diverges