What is the integral of x^2e^{2x^3} ?

The integral of x^2e^{2x^3} is 1/6 e^{2x^3}+C

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integral of x^2e^{2x^3}

\int x^{2} e^{2 x^{3}} d x

\frac{1}{6} e^{2 x^{3}} + C

Solution steps

\int x^{2} e^{2 x^{3}} d x

Apply u-substitution

: \int \frac{e ^{u}}{6} d u

= \int \frac{e ^{u}}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{6} e^{u}

Substitute back

u = 2 x^{3}

= \frac{1}{6} e^{2 x^{3}}

Add a constant to the solution

= \frac{1}{6} e^{2 x^{3}} + C

x \to + 6 lim (8)

\int \frac{ln ^{3} ( x )}{x ^{2}} d x

\frac{d y}{d x} = - 2 y + x

x^{\frac{1}{5}}

x \to 0 lim (\frac{tan ( 3 x )}{3})

What is the integral of x^2e^{2x^3} ?
The integral of x^2e^{2x^3} is 1/6 e^{2x^3}+C