What is the derivative of f(x)=ln(x^9) ?

The derivative of f(x)=ln(x^9) is 9/x

What is the first derivative of f(x)=ln(x^9) ?

The first derivative of f(x)=ln(x^9) is 9/x

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derivative of

f (x) = ln (x^{9})

\frac{9}{x}

Solution steps

\frac{d}{d x} (ln (x^{9}))

Apply the chain rule:

\frac{1}{x ^{9}} \frac{d}{d x} (x^{9})

= \frac{1}{x ^{9}} \frac{d}{d x} (x^{9})

\frac{d}{d x} (x^{9}) = 9 x^{8}

= \frac{1}{x ^{9}} \cdot 9 x^{8}

Simplify

\frac{1}{x ^{9}} \cdot 9 x^{8} : \frac{9}{x}

= \frac{9}{x}

\int x y e^{x y} d y

n = 0 \sum \infty \frac{1}{n ^{n}}

\frac{\partial}{\partial x} (e^{- t} cos (π) x)

\int \frac{ln ( \frac{1}{x} )}{x ^{2}} d x

x \to a lim ([2 f (x) - 5 g (x)])

What is the derivative of f(x)=ln(x^9) ?
The derivative of f(x)=ln(x^9) is 9/x
What is the first derivative of f(x)=ln(x^9) ?
The first derivative of f(x)=ln(x^9) is 9/x