What is the tangent of sqrt(2x+1) ?

The tangent of sqrt(2x+1) is y= 1/(sqrt(2a_{0)+1)}x+sqrt(2a_{0)+1}-(a_{0})/(sqrt(2a_{0)+1)}

Popular >

tangent of sqrt(2x+1)

tangent of

2 x + 1

y = \frac{1}{2 a _{0} + 1} x + 2 a_{0} + 1 - \frac{a _{0}}{2 a _{0} + 1}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0} + 1)

Find the slope of

y = 2 x + 1 : \frac{d y}{d x} = \frac{1}{2 x + 1}

Compute the slope of

y = 2 x + 1

x = a_{0} : m = \frac{1}{2 a _{0} + 1}

Find the line with slope m=

\frac{1}{2 a _{0} + 1}

and passing through

(a_{0}, 2 a_{0} + 1) : y = \frac{1}{2 a _{0} + 1} x + 2 a_{0} + 1 - \frac{a _{0}}{2 a _{0} + 1}

y = \frac{1}{2 a _{0} + 1} x + 2 a_{0} + 1 - \frac{a _{0}}{2 a _{0} + 1}

\frac{d}{d x} (e^{3 x} sin (x^{2}))

7 x^{2}, x^{2} + 3

x \to 3 lim (\frac{x ^{2} - 9}{3 - x})

y^{^{''}} - 8 y^{^{'}} + 16 y = 0

\int \frac{x ^{2} + 1}{( x - 1 ) ^{3}} d x

What is the tangent of sqrt(2x+1) ?
The tangent of sqrt(2x+1) is y= 1/(sqrt(2a_{0)+1)}x+sqrt(2a_{0)+1}-(a_{0})/(sqrt(2a_{0)+1)}