What is the derivative of ((-2x-1)/(-4x+2))^5 ?

The derivative of ((-2x-1)/(-4x+2))^5 is -(5(-2x-1)^4)/(8(2x-1)^6)

What is the first derivative of ((-2x-1)/(-4x+2))^5 ?

The first derivative of ((-2x-1)/(-4x+2))^5 is -(5(-2x-1)^4)/(8(2x-1)^6)

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derivative of

(\frac{- 2 x - 1}{- 4 x + 2})^{5}

- \frac{5 ( - 2 x - 1 ) ^{4}}{8 ( 2 x - 1 ) ^{6}}

Solution steps

\frac{d}{d x} ((\frac{- 2 x - 1}{- 4 x + 2})^{5})

Apply the chain rule:

5 (\frac{- 2 x - 1}{- 4 x + 2})^{4} \frac{d}{d x} (\frac{- 2 x - 1}{- 4 x + 2})

= 5 (\frac{- 2 x - 1}{- 4 x + 2})^{4} \frac{d}{d x} (\frac{- 2 x - 1}{- 4 x + 2})

\frac{d}{d x} (\frac{- 2 x - 1}{- 4 x + 2}) = - \frac{2}{( 2 x - 1 ) ^{2}}

= 5 (\frac{- 2 x - 1}{- 4 x + 2})^{4} (- \frac{2}{( 2 x - 1 ) ^{2}})

Simplify

5 (\frac{- 2 x - 1}{- 4 x + 2})^{4} (- \frac{2}{( 2 x - 1 ) ^{2}}) : - \frac{5 ( - 2 x - 1 ) ^{4}}{8 ( 2 x - 1 ) ^{6}}

= - \frac{5 ( - 2 x - 1 ) ^{4}}{8 ( 2 x - 1 ) ^{6}}

\frac{\partial}{\partial y} (x^{2} + x y^{4})

\int_{1}^{x} \frac{1}{t} d t

\int \frac{1}{( 1 + x ) ^{2}} d x

y = \frac{x - x}{x ^{2}}

ln (1 + 3 x)

What is the derivative of ((-2x-1)/(-4x+2))^5 ?
The derivative of ((-2x-1)/(-4x+2))^5 is -(5(-2x-1)^4)/(8(2x-1)^6)
What is the first derivative of ((-2x-1)/(-4x+2))^5 ?
The first derivative of ((-2x-1)/(-4x+2))^5 is -(5(-2x-1)^4)/(8(2x-1)^6)