What is the solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=6 ?

The solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=6 is y= 5/((x^2+1)^4)+1

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(x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=6

(x^{2} + 1) (\frac{d y}{d x}) + 8 x (y - 1) = 0, y (0) = 6

y = \frac{5}{( x ^{2} + 1 ) ^{4}} + 1

Solution steps

(x^{2} + 1) (\frac{d y}{d x}) + 8 x (y - 1) = 0

Solve separable ODE:

y = \frac{5}{( x ^{2} + 1 ) ^{4}} + 1

y = \frac{5}{( x ^{2} + 1 ) ^{4}} + 1

\frac{\partial}{\partial x} (2 x^{3} y + 1)

x \to 5 lim (x + 2)

x \to 2 lim ((x - 1)^{2} - 1)

\frac{x + 2}{10 - 3 x}

\frac{d}{d x} (x e^{9 x y})

What is the solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=6 ?
The solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=6 is y= 5/((x^2+1)^4)+1