What is area f(x)=x^2-12,g(x)=x-6 ?

The answer to area f(x)=x^2-12,g(x)=x-6 is 125/6

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area f(x)=x^2-12,g(x)=x-6

area

f (x) = x^{2} - 12, g (x) = x - 6

\frac{125}{6}

Decimal Notation

20.83333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{2} - 12 - (x - 6) d x

Solve

\int_{- 2}^{3} x^{2} - 12 - (x - 6) d x : \frac{125}{6}

The area is:

= \frac{125}{6}

\frac{\partial}{\partial x} (sin (4 x^{3} y - 6 x y^{2}))

\frac{d}{d x} (2 (e^{3 x} + 3 e^{3 x} x))

(7.7) (12.11)

x \to 0 lim (\frac{x ^{3} + 4}{x - 2})

\int x 5 x - 2 d x

What is area f(x)=x^2-12,g(x)=x-6 ?
The answer to area f(x)=x^2-12,g(x)=x-6 is 125/6