What is the limit as x approaches 1 of ln(x^5-1) ?

The limit as x approaches 1 of ln(x^5-1) is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of ln(x^5-1)

x \to 1 lim (ln (x^{5} - 1))

Does not exist

Solution steps

x \to 1 lim (ln (x^{5} - 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (ln (x^{5} - 1)) = - \infty

x \to 1 - lim (ln (x^{5} - 1)) =

Does not exist

= Does not exist

\int_{0}^{1} π (x - x^{12}) d x

\int \frac{3 x ^{2} - x + 2 e}{x ^{2}} d x

\int_{2}^{3} π (x + x^{2})^{2} d x

f (x) = \frac{11}{2} - x^{2}, at x = - 2

\int cos (2 x - 3) d x

What is the limit as x approaches 1 of ln(x^5-1) ?
The limit as x approaches 1 of ln(x^5-1) is Does not exist